JEE PYQ: Electromagnetic Induction Question 20
Question 20 - 2019 (12 Apr Shift 1)
The figure shows a square loop L of side 5 cm which is connected to a network of resistances. The whole setup is moving towards right with a constant speed of 1 cm s$^{-1}$. At some instant, a part of L is in a uniform magnetic field of 1 T, perpendicular to the plane of the loop. If the resistance of L is 1.7 $\Omega$, the current in the loop at that instant will be close to:
(1) 60 $\mu$A
(2) 170 $\mu$A
(3) 150 $\mu$A
(4) 115 $\mu$A
Show Answer
Answer: (2)
Solution
Induced emf $e = Bvl = 1 \times 10^{-2} \times 0.05 = 5 \times 10^{-4}$ V. Equivalent resistance: the network gives $R_{eq} = \frac{4 \times 2}{4 + 2} + 1.7 = \frac{4}{3} + 1.7 \approx 3;\Omega$. Current $i = \frac{e}{R} = \frac{5 \times 10^{-4}}{3} = 170;\mu$A.
BETA
