JEE PYQ: Electromagnetic Waves Question 21
Question 21 - 2020 (07 Jan 2020 Shift 1)
If the magnetic field in a plane electromagnetic wave is given by $\vec{B} = 3 \times 10^{-8} \sin(1.6 \times 10^{3}x + 48 \times 10^{10}t) \hat{j}$ T, then what will be expression for electric field?
(1) $\vec{E} = (60 \sin(1.6 \times 10^{3}x + 48 \times 10^{10}t) \hat{k})$ V/m
(2) $\vec{E} = (9 \sin(1.6 \times 10^{3}x + 48 \times 10^{10}t) \hat{k})$ V/m
(3) $\vec{E} = (3 \times 10^{-8} \sin(1.6 \times 10^{3}x + 48 \times 10^{10}t) \hat{j})$ V/m
(4) $\vec{E} = (3 \times 10^{-8} \sin(1.6 \times 10^{3}x + 48 \times 10^{10}t) \hat{i})$ V/m
Show Answer
Answer: (2)
Solution
$E_0 = B_0 C = 3 \times 10^{-8} \times 3 \times 10^{8} = 9$ V/m. $\vec{E} = 9\sin(1.6 \times 10^{3}x + 48 \times 10^{10}t)\hat{k}$ V/m.
BETA
