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JEE PYQ: Electromagnetic Waves Question 26

Question 26 - 2020 (09 Jan 2020 Shift 2)

A plane electromagnetic wave is propagating along the direction $\frac{\hat{i} + \hat{j}}{\sqrt{2}}$, with its polarization along the direction $\hat{k}$. The correct form of the magnetic field of the wave would be (here $B_0$ is an appropriate constant):

(1) $B_0 \frac{\hat{i} - \hat{j}}{\sqrt{2}} \cos\left(\omega t - k \frac{\hat{i} + \hat{j}}{\sqrt{2}}\right)$

(2) $B_0 \frac{\hat{j} - \hat{i}}{\sqrt{2}} \cos\left(\omega t + k \frac{\hat{i} + \hat{j}}{\sqrt{2}}\right)$

(3) $B_0 \hat{k} \cos\left(\omega t - k \frac{\hat{i} + \hat{j}}{\sqrt{2}}\right)$

(4) $B_0 \frac{\hat{i} + \hat{j}}{\sqrt{2}} \cos\left(\omega t - k \frac{\hat{i} + \hat{j}}{\sqrt{2}}\right)$

Show Answer

Answer: (1)

Solution

$\hat{E} = \hat{k}$, propagation $= \frac{\hat{i}+\hat{j}}{\sqrt{2}}$. $\hat{E} \cdot \hat{B} = 0$, so $\hat{B} = \frac{\hat{i}-\hat{j}}{\sqrt{2}}$.


Learning Progress: Step 26 of 41 in this series