JEE PYQ: Electromagnetic Waves Question 33
Question 33 - 2019 (12 Apr 2019 Shift 2)
A plane electromagnetic wave having a frequency $\nu = 23.9$ GHz propagates along the positive z-direction in free space. The peak value of the Electric Field is 60 V/m. Which among the following is the acceptable magnetic field component in the electromagnetic wave?
(1) $\vec{B} = 2 \times 10^{7} \sin(0.5 \times 10^{3} z + 1.5 \times 10^{11} t)\hat{i}$
(2) $\vec{B} = 2 \times 10^{-7} \sin(0.5 \times 10^{3} z - 1.5 \times 10^{11} t)\hat{i}$
(3) $\vec{B} = 60 \sin(0.5 \times 10^{3} x + 1.5 \times 10^{11} t)\hat{k}$
(4) $\vec{B} = 2 \times 10^{-7} \sin(1.5 \times 10^{2} x + 0.5 \times 10^{11} t)\hat{j}$
Show Answer
Answer: (2)
Solution
$B_0 = \frac{E_0}{C} = \frac{60}{3 \times 10^{8}} = 2 \times 10^{-7}$ T. $K = 500$. $\vec{B} = 2 \times 10^{-7} \sin(0.5 \times 10^{3} z - 1.5 \times 10^{11} t)\hat{i}$.
BETA
