JEE PYQ: Electromagnetic Waves Question 34
Question 34 - 2019 (09 Jan 2019 Shift 1)
A plane electromagnetic wave of frequency 50 MHz travels in free space along the positive x-direction. At a particular point in space and time, $\vec{E} = 6.3 \hat{j}$ V/m. The corresponding magnetic field $\vec{B}$, at that point will be:
(1) $18.9 \times 10^{-8} \hat{k}$ T
(2) $2.1 \times 10^{-8} \hat{k}$ T
(3) $6.3 \times 10^{-8} \hat{k}$ T
(4) $18.9 \times 10^{8} \hat{k}$ T
Show Answer
Answer: (2)
Solution
$B = \frac{E}{C} = \frac{6.3}{3 \times 10^{8}} = 2.1 \times 10^{-8}$ T. $\hat{B} = \hat{k}$.
BETA
