JEE PYQ: Electromagnetic Waves Question 36
Question 36 - 2019 (10 Jan 2019 Shift 1)
If the magnetic field of a plane electromagnetic wave is given by (The speed of light $= 3 \times 10^{8}$ m/s) $B = 100 \times 10^{-6} \sin\left[2\pi \times 2 \times 10^{15}\left(t - \frac{x}{c}\right)\right]$ then the maximum electric field associated with it is:
(1) $6 \times 10^{4}$ N/C
(2) $3 \times 10^{4}$ N/C
(3) $4 \times 10^{4}$ N/C
(4) $4.5 \times 10^{4}$ N/C
Show Answer
Answer: (2)
Solution
$E_0 = B_0 \times C = 100 \times 10^{-6} \times 3 \times 10^{8} = 3 \times 10^{4}$ N/C.
BETA
