JEE PYQ: Electromagnetic Waves Question 40
Question 40 - 2019 (11 Jan 2019 Shift 2)
A particle of mass m and charge q is in an electric and magnetic field given by $\vec{E} = 2\hat{i} + 3\hat{j}$; $\vec{B} = 4\hat{j} + 6\hat{k}$. The charged particle is shifted from the origin to the point P$(x = 1; y = 1)$ along a straight path. The magnitude of the total work done is:
(1) $(0.35)q$
(2) $5q$
(3) $(2.5)q$
(4) $(0.15)q$
Show Answer
Answer: (2)
Solution
$W = \vec{F} \cdot \vec{S} = (2q\hat{i} + 3q\hat{j}) \cdot (\hat{i} + \hat{j}) = 2q + 3q = 5q$. (Magnetic force does no work.)
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