JEE PYQ: Electromagnetic Waves Question 41
Question 41 - 2019 (12 Jan 2019 Shift 2)
A light wave is incident normally on a glass slab of refractive index 1.5. If 4% of light gets reflected and the amplitude of the electric field of the incident light is 30 V/m, then the amplitude of the electric field for the wave propagating in the glass medium will be:
(1) 30 V/m
(2) 10 V/m
(3) 24 V/m
(4) 6 V/m
Show Answer
Answer: (3)
Solution
96% of light is refracted. $A_2 = \sqrt{\frac{96}{100} \times \frac{1}{1.5}} \times 30 = 24$ V/m.
BETA
