JEE PYQ: Electrostatics Question 9
Question 9 - 2021 (25 Feb Shift 2)
A charge ‘q’ is placed at one corner of a cube as shown in figure. The flux of electrostatic field $\vec{E}$ through the shaded area is:
(1) $\frac{q}{48\varepsilon_0}$
(2) $\frac{q}{8\varepsilon_0}$
(3) $\frac{q}{24\varepsilon_0}$
(4) $\frac{q}{4\varepsilon_0}$
Show Answer
Answer: (3)
Solution
Charge at corner is shared by 8 cubes. Flux through one cube $= \frac{q}{8\varepsilon_0}$. The shaded face is not adjacent to the corner with charge, so flux through it $= \frac{1}{3} \times \frac{q}{8\varepsilon_0} = \frac{q}{24\varepsilon_0}$.
BETA
