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If the screw on a screw-gauge is given six rotations, it moves by 3 mm on the main scale. If there are 50 divisions on the circular scale the least count of the screw gauge is:
(1) 0.001 cm
(2) 0.02 mm
(3) 0.01 cm
(4) 0.001 mm
Pitch $= \frac{3}{6} = 0.5$ mm. L.C. $= \frac{0.5}{50} = 0.01$ mm $= 0.001$ cm.
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