JEE PYQ: Experimental Physics Question 23
Question 23 - 2019 (09 Jan 2019 Shift 2)
The pitch and the number of divisions, on the circular scale for a given screw gauge are 0.5 mm and 100 respectively. When the screw gauge is fully tightened without any object, the zero of its circular scale lies 3 division below the mean line. The readings of the main scale and the circular scale, for a thin sheet, are 5.5 mm and 48 respectively, the thickness of the sheet is:
(1) 5.755 mm
(2) 5.950 mm
(3) 5.725 mm
(4) 5.740 mm
Show Answer
Answer: (3)
Solution
L.C. $= \frac{0.5}{100} = 0.005$ mm. +ve error $= 3 \times 0.005 = 0.015$ mm. Reading $= 5.5 + (48 \times 0.005) - 0.015 = 5.5 + 0.24 - 0.015 = 5.725$ mm.
BETA
