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The least count of the main scale of a screw gauge is 1 mm. The minimum number of divisions on its circular scale required to measure $5\ \mu$m diameter of a wire is:
(1) 50
(2) 200
(3) 100
(4) 500
$5 \times 10^{-6} = \frac{10^{-3}}{N}$. $N = \frac{10^{-3}}{5 \times 10^{-6}} = 200$.
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