JEE PYQ: Gravitation Question 24
Question 24 - 2020 (04 Sep Shift 2)
A body is moving in a low circular orbit about a planet of mass $M$ and radius $R$. The radius of the orbit can be taken to be $R$ itself. Then the ratio of the speed of this body in the orbit to the escape velocity from the planet is:
(1) $\frac{1}{\sqrt{2}}$
(2) 2
(3) 1
(4) $\sqrt{2}$
Show Answer
Answer: (1)
Solution
Orbital velocity $v_0 = \sqrt{\frac{GM}{R}}$. Escape velocity $v_e = \sqrt{\frac{2GM}{R}}$. $\frac{v_0}{v_e} = \frac{1}{\sqrt{2}}$.
BETA
