JEE PYQ: Gravitation Question 47
Question 47 - 2019 (12 Jan Shift 1)
Two satellites, A and B, have masses $m$ and $2m$ respectively. A is in a circular orbit of radius $R$, and B is in a circular orbit of radius $2R$ around the earth. The ratio of their kinetic energies, $T_A/T_B$, is:
(1) $\frac{1}{2}$
(2) 1
(3) 2
(4) $\sqrt{\frac{1}{2}}$
Show Answer
Answer: (2)
Solution
$T = \frac{1}{2}\frac{GMm}{r}$. $\frac{T_A}{T_B} = \frac{m \cdot 2R}{2m \cdot R} = 1$.
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