JEE PYQ: Gravitation Question 5
Question 5 - 2021 (18 Mar Shift 1)
The time period of a satellite in a circular orbit of radius R is T. The period of another satellite in a circular orbit of radius 9R is:
(1) 9 T
(2) 27 T
(3) 12 T
(4) 3 T
Show Answer
Answer: (2)
Solution
$T^2 \propto R^3$. $\left(\frac{T’}{T}\right)^2 = \left(\frac{9R}{R}\right)^3 = 729$. $T’ = 27T$.