JEE PYQ: Laws Of Motion Question 11
Question 11 - 2021 | 24 Feb Shift 1] (Numerical)
The coefficient of static friction between a wooden block of mass 0.5 kg and a vertical rough wall is 0.2. The magnitude of horizontal force that should be applied on the block to keep it adhere to the wall will be ____ N [$g = 10,\text{ms}^{-2}$]
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Answer: 25
Solution
$f_s = mg$, $N = F$, $f_s = \mu N$. $mg = \mu F$. $F = \frac{mg}{\mu} = \frac{0.5 \times 10}{0.2} = 25$ N.
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