JEE PYQ: Laws Of Motion Question 2
Question 2 - 2021 | 16 Mar Shift 1] (MCQ)
A block of 200 g mass moves with a uniform speed in a horizontal circular groove, with vertical side walls of radius 20 cm. If the block takes 40 s to complete one round, the normal force by the side walls of the groove is :
(1) 0.0314 N
(2) $9.859 \times 10^{-2}$ N
(3) $6.28 \times 10^{-3}$ N
(4) $9.859 \times 10^{-4}$ N [Correct]
Show Answer
Answer: (4)
Solution
$N = m\omega^2 R = m\left(\frac{4\pi^2}{T^2}\right)R$. Given $m = 0.2$ kg, $T = 40$ s, $R = 0.2$ m. $N = 9.859 \times 10^{-4}$ N.
BETA
