JEE PYQ: Laws Of Motion Question 22
Question 22 - 2020 | 07 Jan Shift 2] (Numerical)
Consider a uniform cubical box of side $a$ on a rough floor that is to be moved by applying minimum possible force $F$ at a point $b$ above its centre of mass. If $\mu = 0.4$, the maximum possible value of $100 \times \frac{b}{a}$ for box not to topple before moving is ____.
Show Answer
Answer: 50
Solution
Maximum $b = 0.5a$. $100 \times \frac{b}{a} = 50$.
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