JEE PYQ: Laws Of Motion Question 28
Question 28 - 2019 | 12 Apr Shift 2] (MCQ)
A block of mass 5 kg is (i) pushed in case (A) and (ii) pulled in case (B), by a force $F = 20$ N, making an angle of $30°$ with the horizontal. The coefficient of friction is $\mu = 0.2$. The difference between the accelerations in case (B) and case (A) will be : ($g = 10,\text{ms}^{-2}$)
(1) 0.4 ms$^{-2}$
(2) 3.2 ms$^{-2}$
(3) 0.8 ms$^{-2}$ [Correct]
(4) 0 ms$^{-2}$
Show Answer
Answer: (3)
Solution
$a_B - a_A = 1.86 - 1.06 = 0.8,\text{m/s}^2$.
BETA
