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JEE PYQ: Laws Of Motion Question 31

Question 31 - 2019 | 11 Jan Shift 1] (MCQ)

A slab is subjected to two forces $\vec{F_1}$ and $\vec{F_2}$ of same magnitude F. Force $\vec{F_2}$ is in XY-plane while force $F_1$ acts along z-axis at the point $(2\hat{i} + 3\hat{j})$. The moment of these forces about point O will be :

(1) $(3\hat{i} - 2\hat{j} + 3\hat{k})F$ [Correct]

(2) $(3\hat{i} - 2\hat{j} - 3\hat{k})F$

(3) $(3\hat{i} + 2\hat{j} - 3\hat{k})F$

(4) $(3\hat{i} + 2\hat{j} + 3\hat{k})F$

Show Answer

Answer: (1)

Solution

Net torque $= (3\hat{i} - 2\hat{j} + 3\hat{k})F$.


Learning Progress: Step 31 of 34 in this series