JEE PYQ: Laws Of Motion Question 7
Question 7 - 2021 | 17 Mar Shift 1] (Numerical)
Two blocks (m $= 0.5$ kg and M $= 4.5$ kg) are arranged on a horizontal frictionless table. The coefficient of static friction between the two blocks is $\frac{3}{7}$. Then the maximum horizontal force that can be applied on the larger block so that the blocks move together is ____ N. [Take g as $9.8,\text{ms}^{-2}$]
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Answer: 21
Solution
$a_{\max} = \mu g = \frac{3}{7} \times 9.8$. $F = (M+m)a_{\max} = 5 \times \frac{3}{7} \times 9.8 = 21$ N.
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