JEE PYQ: Laws Of Motion Question 8
Question 8 - 2021 | 17 Mar Shift 2] (Numerical)
A body of mass 1 kg rests on a horizontal floor with which it has a coefficient of static friction $\frac{1}{\sqrt{3}}$. It is desired to make the body move by applying the minimum possible force F N. The value of F will be ____. [Take $g = 10,\text{ms}^{-2}$]
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Answer: 5
Solution
$F_{\min} = \frac{\mu mg}{\sqrt{1+\mu^2}} = \frac{\frac{1}{\sqrt{3}} \times 10}{\frac{2}{\sqrt{3}}} = 5$ N.
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