JEE PYQ: Laws Of Motion Question 9
Question 9 - 2021 | 17 Mar Shift 2] (Numerical)
A boy of mass 4 kg is standing on a piece of wood having mass 5 kg. If the coefficient of friction between the wood and the floor is 0.5, the maximum force that the boy can exert on the rope so that the piece of wood does not move from its place is ____ N. [Take $g = 10,\text{ms}^{-2}$]
Show Answer
Answer: 30
Solution
$N + T = 90$. $T = \mu N = 0.5(90 - T)$. $1.5T = 45$. $T = 30$ N.
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