JEE PYQ: Magnetic Effects Of Current Question 2
Question 2 - 2021 (16 Mar 2021 Shift 2)
The magnetic field in a region is given by $\vec{B} = B_0 \left(\frac{x}{a}\right) \hat{k}$. A square loop of side $d$ is placed with its edges along the $x$ and $y$ axes. The loop is moved with a constant velocity $\vec{v} = v_0 \hat{i}$. The emf induced in the loop is:
(1) $\frac{B_0 v_0^2 , d}{2a}$
(2) $\frac{B_0 v_0 , d}{2a}$
(3) $\frac{B_0 v_0 , d^2}{a}$
(4) $\frac{B_0 v_0 , d^2}{2a}$
Show Answer
Answer: (3) $\frac{B_0 v_0 , d^2}{a}$
Solution
$E_1 = \frac{B_0(x+d)}{a} v_0 , d$, $E_2 = \frac{B_0(x)}{a} v_0 , d$. $E_{\text{net}} = E_1 - E_2 = \frac{B_0 v_0 , d^2}{a}$.
BETA
