JEE PYQ: Magnetic Effects Of Current Question 30
Question 30 - 2020 (09 Jan 2020 Shift 2)
A small circular loop of conducting wire has radius $a$ and carries current $I$. It is placed in a uniform magnetic field $B$ perpendicular to its plane such that when rotated slightly about its diameter and released, it starts performing simple harmonic motion of time period $T$. If the mass of the loop is $m$ then:
(1) $T = \sqrt{\frac{2m}{IB}}$
(2) $T = \sqrt{\frac{\pi m}{2IB}}$
(3) $T = \sqrt{\frac{2\pi m}{IB}}$
(4) $T = \sqrt{\frac{\pi m}{IB}}$
Show Answer
Answer: (3) $T = \sqrt{\frac{2\pi m}{IB}}$
Solution
$\omega = \sqrt{\frac{2\pi IB}{m}}$. $T = \frac{2\pi}{\omega} = \sqrt{\frac{2\pi m}{IB}}$.
BETA
