JEE PYQ: Magnetic Effects Of Current Question 37
Question 37 - 2019 (10 Apr 2019 Shift 1)
Two wires A & B are carrying currents $I_1$ and $I_2$ as shown in the figure. The separation between them is $d$. A third wire C carrying a current $I$ is to be kept parallel to them at a distance $x$ from A such that the net force acting on it is zero. The possible values of $x$ are:
(1) $x = \left(\frac{I_1}{I_1 - I_2}\right)d$ and $x = \frac{I_2}{(I_1 + I_2)}d$
(2) $x = \left(\frac{I_2}{(I_1 + I_2)}\right)d$ and $x = \frac{I_2}{(I_1 - I_2)}d$
(3) $x = \left(\frac{I_1}{(I_1 + I_2)}\right)d$ and $x = \frac{I_2}{(I_1 - I_2)}d$
(4) $x = \pm \frac{I_1 d}{(I_1 - I_2)}$
Show Answer
Answer: (4) $x = \pm \frac{I_1 d}{(I_1 - I_2)}$
Solution
For net force zero: $\frac{I_1}{x} = \frac{I_2}{x-d}$. Solving gives $x = \frac{I_1 d}{I_1 - I_2}$.
BETA
