JEE PYQ: Magnetic Effects Of Current Question 41
Question 41 - 2019 (12 Apr 2019 Shift 2)
Find the magnetic field at point P due to a straight line segment $AB$ of length $6$ cm carrying a current of $5$ A. (See figure)
(1) $2.0 \times 10^{-5}$ T
(2) $1.5 \times 10^{-5}$ T
(3) $3.0 \times 10^{-5}$ T
(4) $2.5 \times 10^{-5}$ T
Show Answer
Answer: (2) $1.5 \times 10^{-5}$ T
Solution
$B = \frac{\mu_0 I}{4\pi r}(\sin\alpha + \sin\beta) = 10^{-7} \times \frac{5}{4 \times 10^{-2}} \times 2\sin 37° = 1.5 \times 10^{-5}$ T.
BETA
