JEE PYQ: Magnetism And Matter Question 11
Question 11 - 2019 (10 Apr 2019 Shift 1)
A moving coil galvanometer allows a full scale current of $10^{-4}$ A. A series resistance of $2$ M$\Omega$ is required to convert the above galvanometer into a voltmeter of range $0 - 5$ V. Therefore the value of shunt resistance required to convert the above galvanometer into an ammeter of range $0 - 10$ mA is:
(1) $500,\Omega$
(2) $100,\Omega$
(3) $200,\Omega$
(4) $195 \times 10^4,\Omega$
Show Answer
Answer: (4) $195 \times 10^4,\Omega$
Solution
$v = i_g(R + G)$, $5 = 10^{-4}(2 \times 10^6 + x)$, $x = -195 \times 10^4,\Omega$
BETA
