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JEE PYQ: Motion In One Dimension Question 16

Question 16 - 2020 (04 Sep Shift 2)

A small ball of mass $m$ is thrown upward with velocity $u$ from the ground. The ball experiences a resistive force $mkv^2$ where $v$ is its speed. The maximum height attained by the ball is:

(1) $\frac{1}{2k}\tan^{-1}\frac{ku^2}{g}$

(2) $\frac{1}{k}\ln\left(1 + \frac{ku^2}{2g}\right)$

(3) $\frac{1}{k}\tan^{-1}\frac{ku^2}{2g}$

(4) $\frac{1}{2k}\ln\left(1 + \frac{ku^2}{g}\right)$

Show Answer

Answer: (4)


Learning Progress: Step 16 of 32 in this series