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JEE PYQ: Motion In One Dimension Question 19

Question 19 - 2020 (05 Sep Shift 2)

The velocity ($v$) and time ($t$) graph of a body in a straight line motion is shown in the figure. The point $S$ is at 4.333 seconds. The total distance covered by the body in 6 s is:

v (m/s) vs t (in s) graph — velocity goes from 0 to 4 m/s at t=0 to t=2 (points A, B), then drops linearly crossing zero at S ≈ 4.333 s (point C), continues to -2 m/s at t=5 (point D), then changes

(1) $\frac{37}{3}$ m

(2) 12 m

(3) 11 m

(4) $\frac{49}{4}$ m

Show Answer

Answer: (1)


Learning Progress: Step 19 of 32 in this series