JEE PYQ: Motion In One Dimension Question 5
Question 5 - 2021 (17 Mar Shift 2)
The velocity of a particle is $v = v_0 + gt + Ft^2$. Its position is $x = 0$ at $t = 0$; then its displacement after time ($t = 1$) is:
(1) $v_0 + g + F$
(2) $v_0 + \frac{g}{2} + \frac{F}{3}$
(3) $v_0 + \frac{g}{2} + F$
(4) $v_0 + 2g + 3F$