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JEE PYQ: Motion In One Dimension Question 5

Question 5 - 2021 (17 Mar Shift 2)

The velocity of a particle is $v = v_0 + gt + Ft^2$. Its position is $x = 0$ at $t = 0$; then its displacement after time ($t = 1$) is:

(1) $v_0 + g + F$

(2) $v_0 + \frac{g}{2} + \frac{F}{3}$

(3) $v_0 + \frac{g}{2} + F$

(4) $v_0 + 2g + 3F$

Show Answer

Answer: (2)


Learning Progress: Step 5 of 32 in this series