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A clock has a continuously moving second’s hand of 0.1 m length. The average acceleration of the tip of the hand (in units of ms$^{-2}$) is of the order of:
(a) $10^{-3}$ (b) $10^{-4}$ (c) $10^{-2}$ (d) $10^{-1}$
$\omega = 2\pi/60 = 0.105$ rad/s. $a = \omega^2 R = (0.105)^2(0.1) \approx 1.1 \times 10^{-3}$ m/s$^2$.
BETA
