JEE PYQ: Motion In Two Dimensions Question 19
Question 19 - 2019 (09 Jan Shift 1)
A particle is moving with a velocity $\vec{v} = K(y\hat{i} + x\hat{j})$, where K is a constant. The general equation for its path is:
(a) $y = x^2 + \text{constant}$ (b) $y^2 = x + \text{constant}$ (c) $y^2 = x^2 + \text{constant}$ (d) $xy = \text{constant}$
Show Answer
Answer: (c)
Solution
$dy/dx = x/y$, so $y,dy = x,dx$. Integrating: $y^2 = x^2 + \text{constant}$.
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