JEE PYQ: Motion In Two Dimensions Question 23
Question 23 - 2019 (11 Jan Shift 1)
A particle is moving along a circular path with a constant speed of 10 ms$^{-1}$. What is the magnitude of the change in velocity of the particle, when it moves through an angle of $60°$ around the centre of the circle?
(a) $10\sqrt{3}$ m/s (b) zero (c) $10\sqrt{2}$ m/s (d) 10 m/s
Show Answer
Answer: (d)
Solution
$|\Delta V| = 2v\sin(\theta/2) = 2 \times 10 \times \sin 30° = 10$ m/s.
BETA
