JEE PYQ: Motion In Two Dimensions Question 4
Question 4 - 2021 (25 Feb Shift 2)
The point A moves with a uniform speed along the circumference of a circle of radius 0.36 m and covers $30°$ in 0.1 s. The perpendicular projection ‘P’ from ‘A’ on the diameter MN represents the simple harmonic motion of ‘P’. The restoration force per unit mass when P touches M will be:
(a) 100 N (b) 50 N (c) 9.87 N (d) 0.49 N
Show Answer
Answer: (c)
Solution
$T = 1.2$ s, $\omega = \frac{2\pi}{1.2}$. Force per unit mass $= \omega^2 A = \left(\frac{2\pi}{1.2}\right)^2 \times 0.36 \approx 9.87$ N.
BETA
