JEE PYQ: Motion In Two Dimensions Question 5
Question 5 - 2021 (26 Feb Shift 1)
A particle is moving with uniform speed along the circumference of a circle of radius R under the action of a central fictitious force F which is inversely proportional to $R^3$. Its time period of revolution will be given by:
(a) $T \propto R^{3/2}$ (b) $T \propto R^2$ (c) $T \propto R^{5/3}$ (d) $T \propto R^{5/2}$
Show Answer
Answer: (b)
Solution
$F = K/R^3$. From $m\omega^2 R = K/R^3$: $\omega^2 \propto 1/R^4$, so $T \propto R^2$.
BETA
