JEE PYQ: Oscillations Question 11
Question 11 - 2021 (24 Feb 2021 Shift 2)
In the given figure, a body of mass $M$ is held between two massless springs, on a smooth inclined plane. The free ends of the springs are attached to firm supports. If each spring has spring constant $k$, the frequency of oscillation of given body is:
(1) $\frac{1}{2\pi}\sqrt{\frac{2k}{Mg\sin\alpha}}$
(2) $\frac{1}{2\pi}\sqrt{\frac{Mg\sin\alpha}{k}}$
(3) $\frac{1}{2\pi}\sqrt{\frac{k}{M}}$
(4) $\frac{1}{2\pi}\sqrt{\frac{2k}{M}}$
Show Answer
Answer: (1)
Solution
Equivalent $K = K + K = 2K$. $f = \frac{1}{2\pi}\sqrt{\frac{2k}{M}}$.
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