JEE PYQ: Oscillations Question 28
Question 28 - 2019 (09 Apr 2019 Shift 1)
A simple pendulum oscillating in air has period $T$. The bob of the pendulum is completely immersed in a non-viscous liquid. The density of the liquid is $\frac{1}{16}$th of the material of the bob. If the bob is inside liquid all the time, its period of oscillation in this liquid is:
(1) $2T\sqrt{\frac{1}{10}}$
(2) $2T\sqrt{\frac{1}{14}}$
(3) $4T\sqrt{\frac{1}{15}}$
(4) $4T\sqrt{\frac{1}{14}}$
Show Answer
Answer: (3)
Solution
$g_{\text{eff}} = g(1 - \frac{1}{16}) = \frac{15g}{16}$. $T’ = 2\pi\sqrt{\frac{l}{15g/16}} = \frac{4}{\sqrt{15}}T$.
BETA
