JEE PYQ: Oscillations Question 30
Question 30 - 2019 (12 Apr 2019 Shift 2)
A spring whose unstretched length is $l$ has a force constant $k$. The spring is cut into two pieces of unstretched lengths $l_1$ and $l_2$ where, $l_1 = nl_2$ and $n$ is an integer. The ratio $k_1/k_2$ of the corresponding force constants will be:
(1) $n$
(2) $\frac{1}{n^2}$
(3) $\frac{1}{n}$
(4) $n^2$
Show Answer
Answer: (3)
Solution
$k \propto \frac{1}{l}$. $\frac{k_1}{k_2} = \frac{l_2}{l_1} = \frac{1}{n}$.
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