JEE PYQ: Oscillations Question 32
Question 32 - 2019 (09 Jan 2019 Shift 2)
A rod of mass ‘M’ and length ‘2L’ is suspended at its middle by a wire. It exhibits torsional oscillations; If two masses each of ’m’ are attached at distance ‘L/2’ from its centre on both sides, it reduces the oscillation frequency by 20%. The value of ratio m/M is close to:
(1) 0.77
(2) 0.57
(3) 0.37
(4) 0.17
Show Answer
Answer: (3)
Solution
Using frequency equations and $f_2 = 0.8 f_1$, solving gives $\frac{m}{M} = 0.37$.
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