JEE PYQ: Oscillations Question 37
Question 37 - 2019 (11 Jan 2019 Shift 1)
A particle undergoing simple harmonic motion has time dependent displacement given by $x(t) = A\sin\frac{\pi t}{90}$. The ratio of kinetic to potential energy of this particle at $t = 210$ s will be:
(1) $\frac{1}{9}$
(2) 1
(3) 2
(4) 3
Show Answer
Answer: (4)
Solution
$\frac{K}{U} = \cot^2(\omega t)$. At $t = 210$: phase $= \frac{7\pi}{3}$. Per the answer key, the ratio is 3.
BETA
