JEE PYQ: Oscillations Question 7
Question 7 - 2021 (18 Mar 2021 Shift 1)
A particle performs simple harmonic motion with a period of 2 second. The time taken by the particle to cover a displacement equal to half of its amplitude from the mean position is $\frac{1}{a}$ s. The value of ‘a’ to the nearest integer is ______
Show Answer
Answer: 6
Solution
$T = 2$ sec. Time to go from mean position to $A/2$ is $t = T/12 = 2/12 = 1/6$ s. So $a = 6$.
BETA
