JEE PYQ: Oscillations Question 8
Question 8 - 2021 (18 Mar 2021 Shift 2)
The function of time representing a simple harmonic motion with a period of $\frac{\pi}{\omega}$ is:
(1) $\sin(\omega t) + \cos(\omega t)$
(2) $\cos(\omega t) + \cos(2\omega t) + \cos(3\omega t)$
(3) $\sin^2(\omega t)$
(4) $3\cos\left(\frac{\pi}{4} - 2\omega t\right)$
Show Answer
Answer: (4)
Solution
Time period $T = \frac{\pi}{\omega}$, so angular frequency $= 2\omega$. Option (d): $3\cos(\frac{\pi}{4} - 2\omega t)$ has angular frequency $2\omega$ and is directly in SHM form.
BETA
