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If ‘M’ is the mass of water that rises in a capillary tube of radius ‘r’, then mass of water which will rise in a capillary tube of radius ‘2r’ is:
(1) M
(2) $\frac{M}{2}$
(3) 4 M
(4) 2 M
$h = \frac{2T\cos\theta}{r\rho g}$, so $m = \rho \pi r^2 h \propto r$. Therefore $m_2 = 2M$.
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