JEE PYQ: Ray Optics Question 31
Question 31 - 2020 (09 Jan Shift 1)
A vessel of depth 2h is half filled with a liquid of refractive index $2\sqrt{2}$ and the upper half with another liquid of refractive index $\sqrt{2}$. The liquids are immiscible. The apparent depth of the inner surface of the bottom of vessel will be:
(1) $\frac{h}{\sqrt{2}}$
(2) $\frac{h}{2(\sqrt{2} + 1)}$
(3) $\frac{h}{3\sqrt{2}}$
(4) $\frac{3}{4}h\sqrt{2}$
Show Answer
Answer: (4)
Solution
Apparent depth, $D = \frac{t_1}{\mu_1} + \frac{t_2}{\mu_2} = \frac{h}{\sqrt{2}} + \frac{h}{2\sqrt{2}} = \frac{3h}{2\sqrt{2}} = \frac{3h\sqrt{2}}{4}$
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