JEE PYQ: Ray Optics Question 5
Question 5 - 2021 (17 Mar Shift 2)
The image of an object placed in air formed by a convex refracting surface is at a distance of 10 m behind the surface. The image is real and is at $\frac{2}{3}$ of the distance of the object from the surface. The wavelength of light inside the surface is $\frac{2}{3}$ times the wavelength in air. The radius of the curved surface is $\frac{x}{13}$ m. The value of ‘$x$’ is _____.
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Answer: (30)
Solution
$\lambda_m = \frac{\lambda_0}{\mu} \Rightarrow \mu = \frac{3}{2}$ $\frac{\mu}{v} - \frac{1}{u} = \frac{\mu - 1}{R}$ $\frac{3}{2 \times 10} + \frac{1}{15} = \frac{\frac{3}{2} - 1}{R}$ $R = \frac{30}{13}$ $= 30$
BETA
