JEE PYQ: Ray Optics Question 52
Question 52 - 2019 (12 Jan Shift 2)
A point source of light, S is placed at a distance L in front of the centre of plane mirror of width $d$ which is hanging vertically on a wall. A man walks in front of the mirror along a line parallel to the mirror, at a distance 2L as shown below. The distance over which the man can see the image of the light source in the mirror is:
(1) $d$
(2) $2d$
(3) $3d$
(4) $\frac{d}{2}$
Show Answer
Answer: (3)
Solution
Total distance $= \frac{3d}{2} + \frac{3d}{2} = 3d$
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