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JEE PYQ: Rotational Motion Question 13

Question 13 - 2021 (24 Feb Shift 1)

Moment of inertia (M.I.) of four bodies, having same mass and radius, are reported as -

$I_1$ = M.I. of thin circular ring about its diameter,

$I_2$ = M.I. of circular disc about an axis perpendicular to disc and going through the centre,

$I_3$ = M.I. of solid cylinder about its axis and

$I_4$ = M.I. of solid sphere about its diameter.

Then:

(1) $I_1 = I_2 = I_3 < I_4$

(2) $I_1 + I_2 = I_3 + \frac{5}{2}I_4$

(3) $I_1 + I_3 < I_2 + I_4$

(4) $I_1 = I_2 = I_3 > I_4$

Show Answer

Answer: (4)


Learning Progress: Step 13 of 70 in this series