JEE PYQ: Rotational Motion Question 15
Question 15 - 2021 (25 Feb Shift 2)
A sphere of radius ‘$a$’ and mass ‘$m$’ rolls along horizontal plane with constant speed $v_0$. It encounters an inclined plane at angle $\theta$ and climbs upward. Assuming that it rolls without slipping, how far up the sphere will travel?
Note: NTA has dropped this question in the final official answer key.
(1) $\frac{v_0^2}{2g\sin\theta}\cdot\frac{1+\mu^2}{1+\mu}$
(2) $\frac{7v_0^2}{10g\sin\theta}$
(3) $\frac{v_0^2}{2g\sin\theta}$
(4) $\frac{2v_0^2}{5g\sin\theta}$
BETA
