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JEE PYQ: Rotational Motion Question 17

Question 17 - 2021 (26 Feb Shift 2)

A cord is wound round the circumference of wheel of radius $r$. The axis of the wheel is horizontal and the moment of inertia about it is $I$. A weight $mg$ is attached to the cord at the end. The weight falls from rest. After falling through a distance $h$, the square of angular velocity of wheel will be:

(1) $\frac{2mgh}{I+mr^2}$

(2) $2gh$

(3) $\frac{2mgh}{I+2mr^2}$

(4) $\frac{2gh}{I+mr^2}$

Show Answer

Answer: (3)


Learning Progress: Step 17 of 70 in this series